In the given figure, D and E are the points on the base BC of `DeltaABC` such that `BD=CE, AD= AE` and `angleADE=angleAED`, prove that `DeltaADB cong DeltaAEC`.

In the given figure, D and E are points on the side BC of a DeltaABC such that BD = CE and AD = AE. Show that DeltaABD~=DeltaACE.

In fig. D and E are points on side BC of triangleABC such that BD=CE and AD=AE. Show that triangleABDequivtriangleACE

In figure ,D and E are Points on side BC of a Delta ABC such that BD=CE and AD=AE.Show that Delta ABD cong Delta ACE.

In figure , D and E are Points on side BC of a Delta ABC such that BD = CE and AD = AE . Show that Delta ABD cong Delta ACE.

In the given figure, AB = AC and AD = AE. Prove that: BD = CE

In Figure,AD=AE and D and E are points on BC such that BD=EC .Prove that AB=AC

In the adjoining figure, AD = DC and bisects angleADC . Prove that DeltaADB cong DeltaCDB .

In the given figure, D is a point on side BC of a DeltaABC and E is a point such that CD = DE. Prove that AB+ACgtBE .

In the given figure, D is a point on side BC of DeltaABC such that (BD)/(CD)=(AB)/(AC) . Prove that AD is the bisector of /_BAC .

In the given figure, D, E and F are the points where the incircle of the DeltaABC touches F the sides BC, CA and AB respectively. Show that AF+ BD + CE = AE + BF + CD = (perimeter of Delta ABC)