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The equation 12x^(2) + 7xy + alpha y^(2)...

The equation `12x^(2) + 7xy + alpha y^(2) + 13x -y + 3=0` represents a pair of perpendicular lines. Then the value of `alpha` is

A

`-19`

B

`7//2`

C

12

D

`-12`

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KCET PREVIOUS YEAR PAPERS-KARNATAKA CET 2001-Mathematics
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