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Let nge5 and bne0. In the binomial expan...

Let `nge5 and bne0`. In the binomial expansion of `(a-b)^(n)`, the sum of the `5^(th) and 6^(th)` terms is zero. Then `a//b` equals

A

`(5)/(n-4)`

B

`(1)/(5(n-4))`

C

`(n-5)/(6)`

D

`(n-4)/(5)`

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