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Inverse of the matrix [[cos 2 theta,-sin...

Inverse of the matrix `[[cos 2 theta,-sin 2 theta],[sin 2 theta , cos 2 theta]]` is

A

`[[cos2theta,-sin2theta],[sin2theta,cos2theta]]` is

B

`[[cos2theta,sin2theta],[sin2theta,-cos2theta]]` is

C

`[[cos2theta,sin2theta],[sin2theta,cos2theta]]` is

D

`[[cos2theta,sin2theta],[-sin2theta,cos2theta]]` is

Text Solution

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The correct Answer is:
D
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