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The chord of the circle x^(2)+y^(2)-y^(2...

The chord of the circle `x^(2)+y^(2)-y^(2)-4x=0` which is bisected at `(1,0)` is perpendicular to the line

A

`x+y=0`

B

`y=x`

C

`y=1`

D

`x=1`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • The equation of the chord of the circle x^(2)+y^(2)-2 x-4 y-20=0 whose mid point is (1,3) is

    A
    `x+y-4=0`
    B
    `3 x+y-6=0`
    C
    `y-3=0`
    D
    `x-1=0`

  • The image of the circle x^(2)+y^(2)-2 x=0 in the line x+y=2 is the circle

    A
    `x^(2)+y^(2)+2 x=0`
    B
    `x^(2)+y^(2)-4 x-2 y-4=0`
    C
    `x^(2)+y^(2)-2 y=0`
    D
    `x^(2)+y^(2)-4 x-2 y+4=0`

  • The ltngth of the chord of the circle x^(2)+y^(2)-6 x+4 y-5=0 intercepted by y -axis is

    A
    3
    B
    6
    C
    8
    D
    4

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