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If A=[(3,2),(1,1)] then A^(2)+xA+yI=0 fo...

If `A=[(3,2),(1,1)]` then `A^(2)+xA+yI=0` for (x,y) =

A

`(-1,3)`

B

`(-4,1)`

C

`(1,3)`

D

`(4,1)`

Text Solution

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The correct Answer is:
B
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