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int (cos2x - cos 2theta)/(cosx- costheta...

`int (cos2x - cos 2theta)/(cosx- costheta)dx` is equal to

A

2(sinx + x cos theta) + C

B

2(sinx - x cos theta) + C

C

2(sinx - 2x cos theta) + C

D

2(sinx - 2x costheta) + C

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The correct Answer is:
A
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