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Delta= |[Ax,x^(2),1],[By,y^(2),1],[Cz, z...

`Delta= |[Ax,x^(2),1],[By,y^(2),1],[Cz, z^(2),1]|` and `Delta_(1)= |[A,B,C],[x,y,z],[zy, zx,xy]|`

A

`Delta= -Delta_(1)`

B

`Delta= Delta_(1)`

C

`Delta= 2Delta_(1)`

D

`Delta ne 2Delta_(1)`

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The correct Answer is:
B
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