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If A=[(2,-2),(-2,2)], then A^n=2^kA , w...

If `A=[(2,-2),(-2,2)], ` then `A^n=2^kA` , where k =

A

`2^(n-1)`

B

n+1

C

`n - 1`

D

2(n-1)

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The correct Answer is:
D
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