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[veca+2vecb-vecc,veca-vecb,veca-vecb-vec...

`[veca+2vecb-vecc,veca-vecb,veca-vecb-vecc]` =

A

0

B

`2[veca,vecb,vecc]`

C

`[veca,vecb,vecc]`

D

`3[veca,vecb,vecc]`

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The correct Answer is:
D
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KCET PREVIOUS YEAR PAPERS-KARNATAKA CET 2019-MATHEMATICS
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