The inward and outward electric flux from a closed surface are respectively `8xx10^(3) and 4xx10^(3)` units. Then the net charge inside the closed surface is

Options

A. `-4xx10^(3)` coulomb
B. `4xx10^(3)` coulomb
C. `(-4xx10^(3))/(epsi_(0))` coulomb
D. `-4xx10^(3)epsi_(0)` coulomb

Answer

D

Explanation

Gauss.s law states that the electric flux `phi_(E)` through any closed surface is equal to `1//epsi_(0)` times the net charge q enclosed by the surface. That is
`phi_(E)=ointvecE*vec(ds)=(q)/(epsi_(0))`.