There are `n_(1)` photons of frequency `v_(1)` in a beam of light. In an equally energetic beam there are `n_(2)` photons of frequency `v_(2)`. Then the correct relation is

Options

A. `(n_(1))/n_(2)=(v_(1))/(v_(2))`
B. `(n_(1))/(n_(2))=1`
C. `(n_1)/(n_(2))=(v_(1)^(2))/(v_(2)^(2))`
D. `(n_(1))/(n_(2))=(v_(2))/(v_(1))`

Answer

D

Explanation

Two beams are equally energetic. Hence,
`n_(1)hv_(1)=n_(2)hv_(2)implies(n_(1))/(n_(2))=(v_(2))/(v_(1))`.