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If a 30 V, 90 W bulb is to be worked in ...

If a 30 V, 90 W bulb is to be worked in 120 V line, the resistance to be connected in series with the bulb is

A

`20Omega`

B

`10Omega`

C

`40Omega`

D

`30Omega`

Text Solution

Verified by Experts

The correct Answer is:
D

For 30V, 90W bulb
`R=(V^(2))/(P)=(30xx30)/(90)=10Omega,I=(P)/(V)=(90)/(30)=3A`
To work with 120V line, `3=(120)/(10+R)impliesR=30Omega`.
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