The dimensions of `a/b` in the equation `P=(a-t^(2))/(bx)` where P is pressure, x is distance and t is time are

Options

A. `M^(2)LT^(-3)`
B. `MT^(-2)`
C. `LT^(-3)`
D. `ML^(3)T^(-1)`

Answer

B

Explanation

`[a]=[T^(2)]`
`Pbx=[T^(2)]`
`[ML^(-1)T^(-2)][b][L]=[T^(2)]`
`[b]=([T^(2)])/([MT^(-2)])=[M^(-1)T^(4)]`
`therefore [(a)/(b)]=([T^(2)])/([M^(-1)T^(4)])=[MT^(-2)]`