Weight of a body of mass m decreases by 1% when it is raised to height h above the earth's surface. If the body is taken to a depth h in a mine, charge in its weight is

Options

A. 0.5% decrease
B. 2% decrease
C. 0.5% increase
D. 1% increase

Answer

A

Explanation

At height `h,g.=g(1-(2h)/(R_(e)))`
`(g.-g)/(g)=-(2h)/(R_(e))=-1%,g"=g(1-(h)/(R_(e)))`
`implies(g"-g)/(g)=-(h)/(R_(e))=-(1)/(2)%=-0.5%`.
Hence weight in mine will decrease by 0.5%.