The equation of a transverse wave travelling along positive x axis with amplitude 0.2 m, velocity 360m/sec and wave-length 60m can be written as

Options

A. `y=0.2 sinpi[6t+(x)/(60)]`
B. `y=0.2sinpi[6t-(x)/(60)]`
C. `y=0.2sin2pi[6t-(x)/(60)]`
D. `y=0.2sin2pi[6t+(x)/(60)]`

Answer

C

Explanation

Equation of plane progressive wave moving in positive direction of x-axis is given by
`y=asin2pin(t-(x)/(v))`
Here a=0.2m, v=360 `ms^(-1),lamda=60m`
`therefore n=(v)/(lamda)=(360)/(60)=6`
The required equation is
`y=0.2sin2pixx6(t-(x)/(360))`
or `y=0.2sin2pi(6t-(x)/(60))`.