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In Young's double slit experiment, the f...

In Young's double slit experiment, the fringe width is `beta`. If the entire arrangement is placed in a liquid of refractive index n, the fringe width becomes

A

`nbeta`

B

`(beta)/(n+1)`

C

`(beta)/(n-1)`

D

`(beta)/(n)`

Text Solution

Verified by Experts

The correct Answer is:
D

`beta=(D)/(d)*lamda`
`therefore (beta)/(beta.)=(lamda)/(lamda.)=nimpliesbeta.=(beta)/(n)`.
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