A wire has a resistance of 6 `Omega`. It is cut into two parts and both half values are connected in parallel. The new resistance is

Options

A. 3`Omega`
B. 6`Omega`
C. 12`Omega`
D. 1.5`Omega`

Answer

D

Explanation

Resistance of wire  `R=p(l)/(A)`
When cut into two parts then the resistance of one part becomes `R’=(p//2)/(A)=(R)/(2)`
When two cut wire is connected in parallel,
`R’=(R’)/(2)=(R)/(4)=(6)/(4)=1.5Omega`