Effective capacitance between A and B in the figure shown is all capacitances are in `muF`

Options

A. `(3)/(14)muF`
B. `(14)/(3)muF`
C. `21muF`
D. `23muF`

Answer

B

Explanation

The point C and D are at the same potential therefore capacitor connected between these two points figure (1) can be neglected. Thus effective capacitance between A and B is =`(6xx3)/(6+3)+(4xx8)/(4+8)` [from fig.(ii)]
`C=2+(8)/(3)=(14)/(3)muF`.