SI unit of permittivity is

Options

A. `C^(2)m^(2)N^(2)`
B. `C^(2)m^(-2)N^(-1)`
C. `C^(2)m^(2)N^(-1)`
D. `C^(-1)m^(2)N^(-2)`

Answer

B

Explanation

`F=(1)/(4piepsilon_(0))(q_(1)q_(2))/(r^(2))`
Substituting units of all `rArr`   `N=(1)/(epsilon_(0))(C^(2))/(m^(2))`   `rArr`     `epsilon_(0)=C^(2)m^(-2)N^(-1)`