Two bodies of masses 1 kg and 2 kg have equal momentum. Then, the ratio of their kinetic energies is

Options

A. `2:1`
B. `3:1`
C. `1:3`
D. `1:1`

Answer

A

Explanation

Kinetic energy =`(p^(2))/(2m)`
Ratio of kinetic energies of two bodies of masses 1 kg and 2 kg having equal momentum is  `(K.E_(1))/(K.F_(2))=(p_(1)^(2)//2m_(1))/(p_(2)^(2)//2m_(2))=(m_(2))/(m_(1))=(2)/(1)`