A perfect gas at `27^(@)C` uis heated at constant pressure so as to double its volume .The increase in temprature of the gas will be

Options

A. `600^(@)`C
B. `327^(@)`C
C. `54^(@)` C
D. `300^(@)`C

Answer

D

Explanation

Here ,`V_(1)=V,V_(2)=2V_(1)`
`T_(1)=27^(@)C` =300 K
According to Charles.s law
`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
or `T_(2)=T_(1)((V_(2))/(V_(1)))=300K ((2V)/(V))=600K`
`T_(2)=327^(@)C`
Increase in temperature ,`DeltaT=T_(2)-T_(1)`