The critical angle of a certain medium is `sin^(-1)((3)/(5))`
The polarizing angle of the medium is

Options

A. `sin^(-1)((4)/(5))`
B. `tan^(-1)((5)/(3))`
C. `tan^(-1)((3)/(4))`
D. `tan^(-1)((4)/(3))`

Answer

B

Explanation

Here,
Critical angle,C=`sin^(1)((3)/(5))`
`therefore sinC(3)/(5)`
As `mu=(1)/(sinC)=(5)/(3)`
According to Brewster.s law
`tani_(p)=mu`
Where `i_(p)` is the polarising angle
`therfore tan i_(p)=(5)/(3)impliesi_(p)=tan^(-1)((5)/(3))`