The electric field at a point due to an electric dipole,on an axis inclined at an angle `theta(lt90^(@))`
to the dipole axis,is perpendicular to the dipole axis ,if the angle `theta` is

Options

A. `tan^(-1)(2)`
B. `tan^(-1)((1)/(2))`
C. `tan^(-1)(sqrt(2))`
D. `tan^(-1)((1)/(sqrt(2)))`

Answer

C

Explanation

tan`phi=(1)/(2)tantheta`…..(i)
According to given problem
`phi+theta=90^(@)`
`phi=90^(@)-theta)`
`tantheta=2tanphi`
`=2tan(90^(@)-theta)`
`tantheta=2cottheta`
`tan^(2)theta=2`
`tantheta=sqrt(2)`
`tantheta=sqrt(2)`
`theta=tan^(1)(sqrt(2))`