In an A.C. Circuit ,V and I are given by V=150 sin (150t) volt and I=150 sin`(150t+(pi)/(3))` ampere.The power dissipated in the circuit is

Options

A. 106 W
B. 150 W
C. 5625 W
D. zero

Answer

C

Explanation

Compare V=150sin(150t) with
`V=V_(0)sinomegat`,we get
`V_(0)=150V`
Compare I=`150sin(150t+(pi)/(3))` with
`I=I_(0)sin(omegat+phi)`, we get
`I_(0)150A,phi=(pi)/(3)=60^(@)`
The power dissipated in A.C circuit is
`P=(1)/(2)V_(0)I_(0)cosphi=(1)/(2)xx150xx150xxcos60^(@)`
`=(1)/(2)xx150xx150xx(1)/(2)=5625W`