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The photoelectric threshold wavelength f...

The photoelectric threshold wavelength for silver in `lambda_(0)`.The energy of the electron ejected from the surface of silver by an incident wavelength `lambda(lambdaltlambda_(0))` will be

A

hc`(lambda_(0)-lambda)`

B

`(hc)/(lambda-lambda)`

C

`(h)/(C)(lambda_(lambda)/(lambdalambda_(0)))`

D

hc`(lambda-lambda)/(lambdalambda_(0))`

Text Solution

Verified by Experts

The correct Answer is:
D
According to Einstein.s photoelectric equation
`K=(hc)/(lambda)-(hc)/(lambda_(0))`
`=hc((1)/(lambda)-(1)/(lambda_(0)))=hc(lambda_(0-lambda)/(lambdalambda_(0)))`
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