When an electron jumps from the orbit n=2 to n=4 ,then wavelength of the radiations absorbed will be
(R is Ryberg's constant)

Options

A. `(16)/(3R)`
B. `(16)/(5R)`
C. `(5R)/(16)`
D. `(3R)/(16)`

Answer

A

Explanation

According to Rydberg formula
`(1)/(lambda)=R[(1)/(n_(i)^(2))-(1)/(n_(f)^(2))]`
Therefore ,the wavelength corresponds to transition from `n_(i)`=2 to `n_(f)=4` is
`(1)/(lambda)R[(1)/(2^(2))-(1)/(4^(2))]=R[(1)/(4)-(1)/(16)]=R[(4-1)/(16)]`
`(1)/(lambda)=(3R)/(16)implieslambda=(16)/(3R)`