An electron of mass `m_(e)` and a proton of mass `m_(p)` are moving with the same speed.The ration of their de-Broglie's wavelengths `(lambda_(e))/(lambda_(p))` is

Options

A. 1
B. 1836
C. `(1)/(1836)`
D. 918

Answer

B

Explanation

de Broglie wavelength ,`lambda=(h)/(mv)`
Where m is the mass and v is the speed of the particle.
As electron and protin both are moving with same speed,therefore the ratio of their de Broglie wavelength is
`(lambda_(2))/(lambda_(p))=(m_(p))/(m_(e))=(1.67xx10^(-27)Kg)/(9.1xx10^(-31)kg)~~1836`