Two heating coils of resistance `10Omega` and `20Omega` are connected in parallel and connected to a battery of emf 12V and internal resistance `1Omega`. The power consumed by them are in the ratio

Options

A. `1:4`
B. `1:3`
C. `2:1`
D. `4:1`

Answer

c

Explanation

As, `P= (V^(2))/(R ) `

For `R_(1)` and `R_(2)` value of V is same .
`therefore P alpha(1)/(R ) Rightarrow(P_(1))/(P_(2))= (R_(2))/(R_(1)) = (20)/(20)`
`P_(1): P_(2) = 2:1`