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A galvanometer coil has a resistance of ...

A galvanometer coil has a resistance of `50 Omega` and the meter shows full scale deflection for a current of 5 mA . This galvanometer is converted into voltmeter of range 0-20V by connecting

A

`3950Omega` in series with galvanometer

B

`40Omega` in series with galvanometer

C

`3950Omega` in parallel with galvanometer

D

`4050Omega` in parallel with galvanometer

Text Solution

Verified by Experts

The correct Answer is:
a
`V=I(R+G)Rightarrow= (V)/(I) -G`
Here , `V= 20V, G= 50omega,i=5mA=5xx10^(-3)A`
`R= (20)/(5xx10^(-3))-50=4000-50=3950omega`
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