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A capcacitor of capacitance 10muF is con...

A capcacitor of capacitance 10`muF` is connected to an AC source and an AC ammeter . If the source voltage varies as `V=50sqrt2` sin 100t, the reading of the ammeter is

A

`50mA`

B

`70.7mA`

C

`5.0MA`

D

`7.07mA`

Text Solution

Verified by Experts

The correct Answer is:
a
`C = 10muF= 10^(-5)F, V_(0)= 50sqrt2sin 100t`
`X_(c)= (1)/(omegaC)= (1)/(100xx10^(-5))= 1000Omega`
`Z=1000Omega, I_(rms) = ? `
`I_(rms)= (V_(rms))/(Z) = (V_(0))/(sqrt2Z)= (50sqrt2)/(ssqrt2xx1000)`
`= 0.05A= 50mA`
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