The pressure and temperature of `4 dm^(3)` of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be

Options

A. `2dm^(3)`
B. `3dm^(3)`
C. `4dm^(3)`
D. `8dm^(3)`

Answer

C

Explanation

`P_(1)=P` `V_(1)=4dm^(3)`,`T_(1)=T`
`P_(2)=2P`, `V_(2)`=? `T_(2)=2T`
From gas equation,
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))rArr(Pxx4)/(T)=(2PxxV)/(2T)`
`rArr` V=4`dm^(3)`.