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0.023g of sodium metal is reacted with 1...

0.023g of sodium metal is reacted with `100 cm^(3)` of water. The pH of the resulting solution is :

A

10

B

11

C

9

D

12

Text Solution

Verified by Experts

The correct Answer is:
D

`M=(0.023xx1000)/(23xx100)=0.01M`
`Na^(+)+OH^(-)hArrNaOH`
`[OH^(-)]=0.01M=10^(-2)M," "pOH=-log(10^(-2))=2`
`pH+pOH=14`
`:." "pH=14-2rArrpH=12`.
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