Excess of silver nitrate solution is added to 100 ml of 0.01 M penta aqua chloro chromium (III) chloride solution .The mass of silver chloride obtained in grams is
[Atomic mass of silver is 108]

Options

A. `287xx10^(-3)`
B. `143.5xx10^(-3)`
C. `143.5xx10^(2)`
D. `287xx10^(-2)`

Answer

A

Explanation

`[Cr(H_(2)O_(5))_(5)Cl]Cl_(2)underset(AgNO_(3))overset(Excess)to`
`[Cr(H_(2)O)_(5)Cl]^(+)NO_(3)^(-)+2AgCldarr`
Thus Meq. Of `Cl^(-)` ions outside=Meq. Of AgCl formed
`therefore` Number of moles of `Cl^(-)` ions present
`=(2xx100xx0.01)/(1000)=0.002 `moles
`therefore` Mass of AgCl=`0.002xx143.5`
=0.287 g=`287xx10^(-3)g`