The empirical formula of a non - electrolyte is `CH_(2)O`. A solution containing 6 g of the compound exerts the same osmotic pressure as that 0.05 M glucose solution at the same temperature. The molecular formula of the compound is

Options

A. `CH_(2)O`
B. `C_(2)H_(4)O_(2)`
C. `C_(4)H_(8)O_(4)`
D. `C_(3)H_(6)O_(3)`

Answer

B

Explanation

For isotonic solution ,`(W_(x))/(M_(x))=(""^(W)C_(6)H_(12)O_(6))/(""^(M)C_(6)H_(12)O_(6))`
`(3)/(M_(x))=(9)/(180)impliesM_(x)=60`
[`because` 0.05 M`C_(6)H_(12)O_(6)` Containing 9 g of glucose]
Molecular weight of electrolyte =60
Empirical formula=`CH_(2)O`
Empirical formula mass =12+2+16=30
Molecular formula =`nxx"empirical formula"`
`n=("molecular mass")/("empirical formula mass")=(60)/(30)=2`
Molecular formula=`2xxCH_(2)O=C_(2)H_(4)O_(2)`