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Following is the substitution reaction i...

Following is the substitution reaction in which -CN replaces -Cl.
`R-Cl+underset("alcoholic")(KCN)underset(Delta)toR-CN+KCl`
To obtain propanonitrile,R-Cl should be

A

Chloroethane

B

1-Chloropropane

C

Chloromethane

D

2-Chloropropane

Text Solution

Verified by Experts

The correct Answer is:
A
Propanonitrile obtained by the reaction between chloroethane anf KCN on heating.
`CH_(3)CH_(2)Cl+underset(("Aalcoholic"))(KCN)underset(Delta)tounderset(("propanonitrile"))(CH_(3)CH_(2)CN)+KCl`.
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Halogenation is a substitution reaction, where halogen replaces one or more hydrogens of hydrocarbon. Chlorine free radical make 1^(@), 2^(@), 3^(@) radicals with almost equal ease, whereas bromine free radicals have a clear preference for the formation of tertiary free radicals. So, bromine is less reactive, and more slective whereas chlorine is less selective and more reactive. The relative rate of abstraction of hydrogen by Br is {:(3^(@),gt,2^(@),gt,1^(@)),((1600),,(82),,(1)):} The relative rate of abstraction of hydrogen by Cl is {:(3^(@),gt,2^(@),gt,1^(@)),((5),,(3.8),,(1)):} How many dichloro products (including stereoisomers) will be formed when R-2-chloropentane reacts with Cl_(2) in presence of UV radiation ?

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