Home
Class 11
CHEMISTRY
If lambda(0) is the threshold wavelengt...

If `lambda_(0)` is the threshold wavelength for photoelectric emission. `lambda` wavelength of light falling on the surface on the surface of metal, and `m` mass of electron. Then de Broglie wavelength of emitted electron is :-

Promotional Banner

Similar Questions

Explore conceptually related problems

If I_(0) is the threshold wavelength for photoelectric emission, 1 the wavelength of light falling on the surface of a metal and m is the mass of the electron, then the velocity of ejected electron is given by

Light of wavelength 500 nm is incident on a metal with work function 2.28 eV. The de Broglie wavelength of the emitted electron is :

Light of wavelength 500 nm is incident on a metal with work function 2.28 eV . The de Broglie wavelength of the emitted electron is

Light of wavelength 500 nm is incident on a metal with work function 2.28 eV . The de Broglie wavelength of the emitted electron is

Light of wavelength 500 nm is incident on a metal with work function 2.28 eV . The de Broglie wavelength of the emitted electron is

If lambda_(0) is the threshold wavelnegth of a metal and lambda is the wavelength of the incident radiation, the maximum velocity of the ejected electron from the metal would be

The threshold frequency and the threshold wavelength of photoelectric emission from a metal surface are f_(0) and lamda_(0) . The frequency and the wavelength of incident light are f and lamda . Then