The height above the surface of earth at which acceleration due to gravity is half the acceleration due to gravity at surface of eart is `(R=6.4xx10^(6)m)`

Acceleration due to gravity is __ at the surface of earth.

The height above the surface of the earth where acceleration due to gravity is 1/64 of its value at surface of the earth is approximately.

The height above the surface of the earth where acceleration due to gravity is 1/64 of its value at surface of the earth is approximately.

Find the height (in terms of R, the radius of the earth) at which the acceleration due to gravity becomes g/9(where g=the acceleration due to gravity on the surface of the earth) is

At what height above the surface of the earth will the acceleration due to gravity be half of its value on the earth's surface ? Radius of the earth =6400 km.

At what depth below the surface of the earth acceleration due to gravity will be half its value at 1600 km above the surface of the earth ?

At what depth below the surface of the earth acceleration due to gravity will be half its value at 1600 km above the surface of the earth ?

The height at which the acceleration due to gravity becomes (g)/(9) (where g = the acceleration due to gravity on the surface of the Earth) in terms of R, the radius of the Earth, is: