An element with atomic mass 60 having fcc structure has a density of `6.23 "g/cm"^3`.What is the edge length of unit cell ?

An element (at mass 60) havind FCC structure has a density of 6.23"g cm"^(-3) . What is the edge length of the unit cell ?

An element (atomic mass = 60) having fcc structure has density of 6.23 g cm^(-3) . The edge length of its unit cell is :

An element (atomic mass=60) having face centred cubic unit cell has a density of '6.23 gcm^-3'. What is the edge length of unit cell?

An element (at. mass = 60) having face centred cubic unit cell has a density of 6.23g cm^(-3) . What is the edge length of the unit cell? (Avogadro's constant = 6.023 xx 10^(23) mol^(-1) )

A element X with atomic mass 60 g/mol has a density of 6.23"g cm"^(-3) . If the edge length of the unit cell is 400 pm, identify the type of the cubic unit cell. Calculate the radius of the atoms of the element.

A element X with atomic mass 60 g/mol has a density of 6.23"g cm"^(-3) . If the edge length of the unit cell is 400 pm, identify the type of the cubic unit cell. Calculate the radius of the atoms of the element.

A element X with atomic mass 60 g/mol has a density of 6.23"g cm"^(-3) . If the edge length of the unit cell is 400 pm, identify the type of the cubic unit cell. Calculate the radius of the atoms of the element.

A element X with atomic mass 60 g/mol has a density of 6.23"g cm"^(-3) . If the edge length of the unit cell is 400 pm, identify the type of the cubic unit cell. Calculate the radius of the atoms of the element.