(3y-2)+i(7-2x)=0

Find the following products: (i) (0.9x+0.7y)(0.81x^(2)-0.63xy+0.49y^(2)) (ii) ((2x)/(5)-(3y)/(7))((9y^(2))/(49)+(4x^(2))/(25)+(6xy)/(35))

I. x^(2) -7x + 12 = 0" "II. 3y^(2) - 11y + 10 = 0

I. 5x^(2) + 2x - 3 = 0" "II. 2y^(2) + 7y + 6 = 0

I. x^(2) - 3x + 2 = 0" "II. 2y^(2) - 7y+6 = 0

I. 3x^(2) - 7x+2 = 0" " II. 2y^(2) - 11y + 15 = 0

I. 3x^(2) - 22x + 7 = 0" "II. Y^(2) - 20y+91 = 0

A point which lies between 2x+3y-7=0 and 2x+3y+12-0 is (i)(5,1)( (ii) (-1,3)( iii) (-3,-5)( iv )(7,-1)

If (3+i)x + (1-2i)y + 7i = 0 , then the values of x and y respectively are

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

Find the greatest value of x^(3)y^(4) if 2x+3y=7 and x>=0,y>=0 .