`log(3x-2)+log(3x+2)=5log2`

Solve for x : (i) log_(10) (x - 10) = 1 (ii) log (x^(2) - 21) = 2 (iii) log(x - 2) + log(x + 2) = log 5 (iv) log(x + 5) + log(x - 5) = 4 log 2 + 2 log 3

lim_(x rarr 3) (log(2x-3)-log(3x + 2))/(log(2x +1))= _______.

Find x, if log x^(3) - log 3x =2 log 2 + log 3 ,

Solve for x: a) log_(x)2. log_(2x)2 = log_(4x)2 b) 5^(logx)+5x^(log5)=3(a gt 0), where base of log is 3.

Solve (log_(3)x)(log_(5)9)- log_x 25 + log_(3) 2 = log_(3) 54 .

Solve (log_(3)x)(log_(5)9)- log_x 25 + log_(3) 2 = log_(3) 54 .

Solve (log_(3)x)(log_(5)9)- log_x 25 + log_(3) 2 = log_(3) 54 .

Solve (log_(3)x)(log_(5)9)- log_x 25 + log_(3) 2 = log_(3) 54 .