A thin rod of mass `M` and length `L` is bent into a circular ring. The expression for moment of inertia of ring about an axis passing through its diameter is

A wire of mass m and length l is bent in the form of circular ring. The moment of inertia of the ring about its axis is

Find the expression for moment of inertia of a thin uniform rod about an axis passing through its centre and perpendicular to its length

A thin wire of mass m and length l is bent in the form of a ring . Moment of inertia of that ring about an axis passing through its centre and perpendicular to its through its centre and perpendicular to its plane is

A thin wire of mass m and length l is bent in the form of a ring . Moment of inertia of that ring about an axis passing througfh its centre and perpendicular to its plane is

A thin uniform wire of mass m and length l is bent into to shape of a semicircle. The moment of inertia of that wire about an axis passing through its free ends is

A thin uniform wire of mass m and length l is bent into to shape of a semicircle. The moment of inertia of that wire about an axis passing through its free ends is

A thin wire of mass M and length L is turned into a ring. The moment of inertia about its axis will be:

A thin rod of length L of mass M is bent at the middle point O at an angle of 60^@ . The moment of inertia of the rod about an axis passing through O and perpendicular to the plane of the rod will be