`P(AuuB)=P(A)-P(B)+P(AnnB)`

Statement 1: The probability of drawing either an ace or a king from a pack of card in a single draw is 2/13. Statement 2: for two events Aa n dB which are not mutually exclusive, P(AuuB)=P(A)+P(B)-P(AnnB)dot

Statement 1: The probability of drawing either an ace or a king from a pack of card in a single draw is 2/13. Statement 2: for two events Aa n dB which are not mutually exclusive, P(AuuB)=P(A)+P(B)-P(AnnB)dot

Statement 1: The probability of drawing either an ace or a king from a pack of card in a single draw is 2/13. Statement 2: for two events Aa n dB which are not mutually exclusive, P(AuuB)=P(A)+P(B)-P(AnnB)dot a) statement 1 and 2 both are true and statement 2 is correct explaination for statement 1. (b) statement 1 and 2 both are true but statement 2 is not the correct explaination for statement 1. (c) only statement 1 is true. (d) both the statements are false.

If A and B are two events, then P( A nnB)=?? a.) P( A )P( B ) b.) 1-P(A)-P(B) c.) P(A)+P(B)-P(AuuB) d.) P(B)-P(AnnB)

If Aa n dB are two events, the probability that exactly one of them occurs is given by P(A)+P(B)-2P(AnnB) P(Ann B )+P( A nnB) P(AuuB)-P(AnnB) P( A )+P( B )-2P( A nn B )

If A and B are two events, then P( A nnB)= P( A )P( B ) b. 1-P(A)-P(B) c. P(A)+P(B)-P(AuuB) d. P(B)-P(AnnB)

(i) If P is a probability function, show that for any two events A, B. P(AnnB) le P(A) le P(AuuB) le P(A)+P(B) (ii) For any two events A,B show that P(barAnnbarB)=1+P(AnnB)-P(A)-P(B)

If A and B are events such that P(A'uuB') = (3)/(4), P(A'nnB') = (1)/(4) and P(A) = (1)/(3) , then find the value of P(A' nn B)

If A and B are events such that P(A'uuB') = (3)/(4), P(A'nnB') = (1)/(4) and P(A) = (1)/(3) , then find the value of P(A' nn B)