यदि `root(3)(a-ib)=x-iy` तो सिद्ध करें की
`root(3)(a+ib)=x+iy`.

If root(3)(a+ib) = x + iy, prove that : root(3)(a-ib) = x- iy .

If sqrt(a-ib) = x-iy , prove that sqrt(a+ib) =x+iy.

If sqrt(a+ib)=x+iy then prove that sqrt(a-ib)=x-iy

If sqrt(a+ib)=x+iy , then value of sqrt(a-ib) is:

If sqrt(a+ib) =x+iy then possible value of sqrt(a-ib) is-

If sqrt(a+ib) = x+iy , then possible value of sqrt((a-ib) is (a,b,x,y in R)

If sqrt(a+ib)=x+iy ,prove that sqrt(a-ib)=x-iy

If sqrt(a + ib) = x + iy, then possible value of sqrt(a - ib) is

If (a+ib)/(c+id)=x+iy prove that, (a-ib)/(c-id)=x-iy

If sqrt(a+ib)=x+iy, then possible value of sqrt(a-ib) is x^(2)+y^(2) b.sqrt(x^(2)+y^(2)) c.x+iydx-iy e.sqrt(x^(2)-y^(2))