A railway track running north south has two parrallel rails 1.0 m apart. Calculate the e.m.f. induced between the rails when a train passes at a speed of 90 km `h^(-1)`. Horizontal component of earth's magnetic field at that plane is `0.3 xx 10^(-4) T` and angle of dip is `60^(@)`.

A railway track running North South has two parallel rails 1.0m apart. Calculate the value of induced e.m.f. between the rails when a train passes at a speed of 90 kmh(-1) . Horizontal component of earth’s field at that place is 0.3xx1O(-4) Wbm(-2) and angle of dip is 60^@ .

The rails of a railway track are 1.80 m apart and assumed to be insulated from one another. Calculate the emf induced between the rails if a train is passing at 120 km. h^(-1) . Assume that the horizontal component of earth's magnetic field, H=0.36xx10^(-4)T and angle of dip. theta=tan^(-1)(1.026) .

Calculate the e.m.f. induced between the ends of an axle 1.75 m long of a railway carriage travelling at the rate of 50 km h^-1 . The vertical component of the earth's magnetic field 0.5 xx 10^-4 weber m^-2

The horizontal component of earths's magnetic field at a place is 0.3 xx 10^-4T . If the angle of dip is 60^@ , what is the total earth's magnetic field?

The rails ofa railway track are I.Sm apart and assumed to be insulated from one another. Calculate the EMF that will exist between the rails if a train is passing at 100 km/hr. Assume the horizontal component of earth's magnetic field is 0.36xx10^(-4)T and tan theta=1.036 where theta is the angle of dip.

Calculate earth's magnetic field at a place where angle of dip delta is 60^(@) and horizontal component of earth's magnetic field is 0.3 G

Calculate earth's magnetic field at a place where angle of dip delta is 60^(@) and horizontal component of earth's magnetic field is 0.3 G

A metergauge train runs northwards with a constant speed of 22 m/s on a horizontal track.The vertical component of the earth's magnetic field at that place is 3 xx 10^-4 T . the emf induced in its axle is