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[" Electrons with de-Broglie wavelength ...

[" Electrons with de-Broglie wavelength "lambda" fall on the target in an "X" -ray tube.The cut-off wavelength of the "],[" emitted "X" -rays is "],[[" (A) "lambda_(0)=(2mc lambda^(2))/(h)," (B) "lambda_(0)=(2h)/(m)," (C) "lambda_(0)=(2m^(2)c^(2)lambda^(3))/(h^(2))," (D) "lambda_(0)=lambda]]

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