Home
Class 12
CHEMISTRY
Temperature coceficient, mu=(k(35^(@)C))...

Temperature coceficient, `mu=(k_(35^(@)C))/(k_(25^(@)C))` of a reaction is `1.82`. Calculate the energy of activation in colories `(R=1.987 "cal degree"^(-1)"mol"^(-1))`

Promotional Banner

Similar Questions

Explore conceptually related problems

The ratio of rate constants of a reaction at 300K and 291K is 2. Calculate the energy of activation. ("Given "R = "8.314JK"^(-1)" mol"^(-1)) .

The rate of a reaction triples when temperature changes from 50 to 100^(@)C. Calculate the energy of activation for such a reaction (R=8.314" J K"^(-1)" mol"^(-1))

The rate of reaction triples when temperature changes form 20^(@)C to 50^(@)C . Calculate the energy of activation for the reaction (R= 8.314JK^(-1)mol^(-1)) .

a) The rate of a particular reaction doubles when the temperature changes from 300 K to 310 K. Calculate the energy of activation of the reaction. [Given : R="8.314 JK"^(-1)" mol"^(-1) ].

The rate of a reaction increases four times when the temperature changes from 300K to 320 K. Calculate the energy of activation of the reaction. (R=8.314JK^(-1)mol^(-1))

The specific reaction rate of a reaction quadruples when temperature changes from 30°C to 50°C. Calculate the energy of activation of the reaction [Given : R = 8.314 "JK"^(-1) "mol"^(-1) ]