When the resistance in left and right gap of a mere bridge are `101Omega` and `1Omega` respectively, the null point is found at 99.5 cm. When the resistances are interchanged the null point is now at 0.7cm. Calculate the end-corrections of the metre bridge.

The resistances in the left and right gaps of a metre bridge are 10 Omega and 30 Omega respectively. If the bridge is balanced, then the distance of the null point from the centre of the wire is

The points in a metre bridge is at 35.6 cm. if the resistances in the gaps are interchanged, the new balance point is

In a metre bridge expt, when the resistances in the gaps are interchanged the balance point is increases by 10 cm. The ratio of the resistances is

With resistances P and Q in the left and right gaps of a metre bridge respectively, the null point divides the wire in the ratio 1 : 2 . If P and Q are increased by 20 Omega each, the null point divides the wire in the ratio 3 : 4, then the resistances P and Q are given as :

With resistances P and Q in the left gap and right gap respectively, of a meter bridge. The null point is obtained at 60 cm from left end. When Q is increased by 10Omega the null point is obtained at 40 cm from left end. The values of P and Q are

In a meter-bridge experiment with a resistance R_(1) in left gap and a resistance X in a right gap. null point is obtained at 40 cm from the left emf. With a resistance R_(2) in the left gap, the null point is obtainned at 50 cm from left hand. Find the position of the left gap is containing R_(1) and R_(2) (i) in series and (ii) in parallel.