Calculate "pH" of given mixture at `90^(@)C` temperature : 0.01M,2L of `H_(2)SO_(4)`+0.02M , 3L of `Ba(OH)_(2)`
`K_(W)`=`10^(-12)`at `90^(@)C` and log2=0.3

Calculate the pH of resulting mixtures. 10 " ml of " 0.1 M H_(2)SO_(4) + 10 " ml of " 0.1 M KOH

Calculate the pH of the resultant mixtures : 10mL of 0.2 M Ca(OH)_(2)+"25 mL of 0.1 M HCl"

Calculate the pH of resulting mixtures. 10" ml of " 0.2 M Ca (OH)_(2) + 25 " ml of " 0.1 M HCl

Calculate pH of mixture of (400mL,(1)/(200)M H_(2)SO_(4))+(400mL.(1)/(100)M HCl)+(200mL of water) Take log2=0.3

Calculate the pH of the resultant mixture: a. 10 mL of 0.2M Ca(OH)_(2)+25 mL of 0.1 M HCl b. 10 mL of 0.01 M H_(2)SO_(4) + 10 mL of 0.01 M Ca(OH)_(2) . c. 10 mL of 0.1 M H_(2)SO_(4)+ 10 mL of 0.1 M KOH .

Calculate the pH of solution obtained by mixing 10 ml of 0.1 M HCl and 40 ml of 0.2 M H_(2)SO_(4)

Calculate pH of a solution of given mixture ( 0.1 "mol " CH_(3)COOH+0.2 mol CH_(3)COONa ) in 100 ml of mixture. K=2xx10^(-5) .

Calculate the pH of the resultant mixtures : (a) 10 mL of 0.2 M Ca(OH)_(2) + 25 mL of 0.1 M HCl (b)10 mL of 0.01 M H_(2) SO_(4) + 10 mL of 0.01 M Ca(OH_(2)) (c) 10 mL of 0.1 M H_(2) SO_(4) + 10 mL of 0.1 M KOH