In A.P, `a_(3)=9, a_(10)=21` then `S_(12)=`..........

If a_(1),a_(2),.........,...,a_(24) are in A.P and a_(1)+a_(5)+a_(10)+a_(15)+a_(20)+a_(24)=225, then a_(1)+a_(2)+a_(3)+.........+a_(24)=

The sixth term of an A.P.,a_(1),a_(2),a_(3),.........,a_(n) is 2. If the quantity a_(1)a_(4)a_(5), is minimum then then the common difference of the A.P.

Suppose a_(1),a_(2)… are in A.P. If a_(8): a_(5)= 3:2, then a_(17) : a_(23) is :

If a_(1),a_(2)a_(3),….,a_(15) are in A.P and a_(1)+a_(8)+a_(15)=15 , then a_(2)+a_(3)+a_(8)+a_(13)+a_(14) is equal to

let a_(1),a_(2),a_(3)...... be an AP such that (a_(1)+a_(2)+............+a_(p))/(a_(1)+a_(2)+............+a_(q))=(p^(3))/(q^(3)) then a_(/)a_(21)

If a_(1), a_(2), a_(3),........, a_(n) ,... are in A.P. such that a_(4) - a_(7) + a_(10) = m , then the sum of first 13 terms of this A.P., is:

Given a_(1),a_(2),......,a_(12) are in G.P. If a_(4)*a_(9)=2019 then value of (a_(2)a_(11)+a_(3)a_(10)+a_(5)a_(8)+a_(6)a_(7))/(a_(4)a_(9)) is equal to

If the sum of first 11 terms of an A.P., a_(1),a_(2),a_(3),.... is 0(a_(1)!=0) then the sum of the A.P., a_(1), a_(3),a_(5), ......,a_(23) is k a_(1) , where k is equal to :

STATEMENT-1 : If a, b, c are in A.P. , b, c, a are in G.P. then c, a, b are in H.P. STATEMENT-2 : If a_(1) , a_(2) a_(3) ……..a_(100) are in A.P. and a_(3) + a_(98) = 50 " then" a _(1) + a_(2) +a_(3) + ….+ a_(100) = 2500 STATEMENT-3 : If a_(1) , a_(2) , ....... ,a_(n) ne 0 then (a_(1) + a_(2)+ a_(3) + .......+ a_(n))/(n) ge (a_(1) a_(2) .........a_(n) )^(1//n)

Let a_(1),a_(2),a_(3)......... be in A.P. and h_(1),h_(2),h_(3)......, in H.P. If a_(1)=2=h_(1), and a_(30)=25=h_(30) then a_(7)h_(24)+a_(14)+a_(17)=